(x+1)(x+2)=x^2-16

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Solution for (x+1)(x+2)=x^2-16 equation: 


Simplifying
(x + 1)(x + 2) = x2 + -16

Reorder the terms:
(1 + x)(x + 2) = x2 + -16

Reorder the terms:
(1 + x)(2 + x) = x2 + -16

Multiply (1 + x) * (2 + x)
(1(2 + x) + x(2 + x)) = x2 + -16
((2 * 1 + x * 1) + x(2 + x)) = x2 + -16
((2 + 1x) + x(2 + x)) = x2 + -16
(2 + 1x + (2 * x + x * x)) = x2 + -16
(2 + 1x + (2x + x2)) = x2 + -16

Combine like terms: 1x + 2x = 3x
(2 + 3x + x2) = x2 + -16

Reorder the terms:
2 + 3x + x2 = -16 + x2

Add '-1x2' to each side of the equation.
2 + 3x + x2 + -1x2 = -16 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
2 + 3x + 0 = -16 + x2 + -1x2
2 + 3x = -16 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
2 + 3x = -16 + 0
2 + 3x = -16

Solving
2 + 3x = -16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 3x = -16 + -2

Combine like terms: 2 + -2 = 0
0 + 3x = -16 + -2
3x = -16 + -2

Combine like terms: -16 + -2 = -18
3x = -18

Divide each side by '3'.
x = -6

Simplifying
x = -6

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